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16x^2=1544
We move all terms to the left:
16x^2-(1544)=0
a = 16; b = 0; c = -1544;
Δ = b2-4ac
Δ = 02-4·16·(-1544)
Δ = 98816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{98816}=\sqrt{256*386}=\sqrt{256}*\sqrt{386}=16\sqrt{386}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{386}}{2*16}=\frac{0-16\sqrt{386}}{32} =-\frac{16\sqrt{386}}{32} =-\frac{\sqrt{386}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{386}}{2*16}=\frac{0+16\sqrt{386}}{32} =\frac{16\sqrt{386}}{32} =\frac{\sqrt{386}}{2} $
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